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A circuit has a line of 50A. How nuny lamps of rating 40W, 220 V can simultaneously run on this line safely ? |
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Answer» Solution :I = `(P)/(V) = (40W)/(220 V)= (2)/(11) A = 0.18 ` AMP . `(2)/(11) ` A or 0.18 A currents is required by one lamp. Current RATING (MAXIMUM current ) = 5A. `therefore` No of LAMPS = `("Current rating ")/("Current through one lamp")` = `(5)/(0.18)` = 27 |
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