1.

A circuit has a line of 50A. How nuny lamps of rating 40W, 220 V can simultaneously run on this line safely ?

Answer»

Solution :I = `(P)/(V) = (40W)/(220 V)= (2)/(11) A = 0.18 ` AMP .
`(2)/(11) ` A or 0.18 A currents is required by one lamp.
Current RATING (MAXIMUM current ) = 5A.
`therefore` No of LAMPS = `("Current rating ")/("Current through one lamp")`
= `(5)/(0.18)` = 27


Discussion

No Comment Found