1.

A circuit is given in the figure below. We can infer that ________(a) The circuit follows Reciprocity Theorem(b) The circuit follows Millman’s Theorem(c) The circuit follows Superposition Theorem(d) The circuit follows Tellegen TheoremI have been asked this question in an interview.Asked question is from Advanced Problems on Reciprocity Theorem topic in section Useful Theorems in Circuit Analysis of Network Theory

Answer»

Correct choice is (a) The circuit follows Reciprocity Theorem

The explanation: Let us CONSIDER this circuit,

Equivalent Resistance REQ = 20 + [30 || (20 + (20||20))]

= 20 + [30 || (20 + \(\FRAC{20×20}{20+20}\))]

= 20 + [30 || (20+10)]

= 20 + [30 || 30]

= 20 + \(\frac{30 × 30}{30+30}\)

= 20 + 15 = 35 Ω

The current drawn by the circuit = \(\frac{200}{35}\) = 5.71 A

Now, by using current division rule, we get, I1 = 1.43 A

Again, let us consider this circuit,

Equivalent Resistance, REQ = [[((30 || 20) + 20) || 20] + 20]

= \(\BIG[\Big[\left(\left(\frac{30 × 20}{30+20}\right) + 20\right) || 20\Big] + 20\Big]\)

= [[(12 + 20) || 20] + 20]

= [[32 || 20] + 20]

= \(\Big[\left(\frac{32 × 20}{32+20}\right) + 20\Big]\)

= [12.31 + 20] = 32.31 Ω

The current drawn by the circuit = \(\frac{200}{32.31}\) = 6.19 A

Now, by using current division rule, we get, I2 = 1.43 A.

Since I1 = I2, the circuit follows Reciprocity Theorem.



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