1.

A circular disc of radiusabout on its circumference. The periodof oscillation will be:(a) 1.09 sec(b) 3.45 sec(c) 4.06 sec(d) 5.07 sec

Answer»

the moment of the inertia of the disc about an axis passing throw it's center of gravity and perpendicular to it's plane will be given by 1/2MK²= 1/2*M*(0.2)²k²= 0.02distance of center of oscillation from the point of suspension is = L= PO= k^2/L+L = 0.3mperiod of oscillation = T = 2π√L/g= 2*3.14*√0.3/9.8=1.098 second



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