A circular hole of radius `r` is made in a disk of radius `R` and of uniform thickness at a distance `a` from the centre of the disk. The distance of the new centre of mass from the original centre of mass is A. `(aR^(2))/(R^(2)-r^(2))`B. `(ar^(2))/(R^(2)-r^(2))`C. `(a(R^(2)-r^(2)))/(r^(2))`D. `(a(R^(2)-r^(2)))/(R^(2))`

A circular hole of radius `r` is made in a disk of radius `R` and of u

1.	A circular hole of radius `r` is made in a disk of radius `R` and of uniform thickness at a distance `a` from the centre of the disk. The distance of the new centre of mass from the original centre of mass is A. `(aR^(2))/(R^(2)-r^(2))`B. `(ar^(2))/(R^(2)-r^(2))`C. `(a(R^(2)-r^(2)))/(r^(2))`D. `(a(R^(2)-r^(2)))/(R^(2))`
Answer» Correct Answer - B `x=(r^(2)a)/(R^(2)-r^(2))`

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