A circular iron-plate of thickness `(2)/(3)` cm is made by beating an – InterviewSolution

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1.	A circular iron-plate of thickness `(2)/(3)` cm is made by beating an iron-sphere of diameter 4 cm. What will be the radius of the iron-plate?
Answer» The radius of the iron-sphere `-(4)/(2)`cm=2cm. `therefore` the volume of the iron-sphere `=(4)/(3)pixx2^(3)cc.=(32pi)/(3)cc.` Let the radius of the iron-plate be r cm. `therefore` the area of the iron-plate `=pir^(2)` sq-cm. Since the iron-plate is of thickness `(2)/(3)` cm, its volume =`(2)/(3)pir^(2)` cu.cm. As per question `(2)/(3)pir^(2)=(32pi)/(3)rArr r^(2)=16rArr r=sqrt(16)=4` Hence the radius of the circular iron-plate=4 cm.

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