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    				| 1. | A sphere of greates volume is cut off from a metal hemisphere of radius 6cm. If the cost of 1 cc metal be ₹42, then what will be the cost of the remaining hemisphere? | 
| Answer» The radius of the metal hemisphere =6 cm. So, the volume of the hemisphere `=(2)/(3)xx6^(3)`cc. Again, the diameter of the greates sphere that can be cut off from the hemisphere will be 6 cm . So, its radius will be `(6)/(2)`cm =3 cm. `:.` the volume of the greatest sphere cut off frome the hemisphere `=(4)/(3)pi3^(3)`cc. `:.` The volume of the remaining part of the hemisphere `=((2)/(3)pixx6^(3)-(4)/(3)pi3^(3)) "cc" =(2)/(3)pi(216-54)"cc"=(2)/(3)pixx162"cc"=108` So, the cost of the remaining part of the metal hemishere =₹`108xx(22)/(7)xx42=₹14256.` Hence the required cost=₹14256. | |