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A circular ring of mass 1kg and radius 0.2mexecutes 10 revolutions per sec. Its angularmomentum would be - (kg-m2/sed)(A) 0.025(B) 0.25(C) 2.5(D) 25 |
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Answer» L = Iw here for a circular ring rotating about its axis I = MR^2= 1x(0.2)^2= 0.04 kg.m^2 and w = 10 rps = 62.83 rad/s so, we have L = 0.4 x 62.83 thus, angular momentum L = 2.513 kg.m^2/s |
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