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A closed loop of cross-sectional area `10^(-2) m^(2)` which has inductance `L = 10 mH` and negligible resistance is placed ti time- varying magnetic field. Figure shows the variation of `B` with time for the intervel `4 s`. The field is perpendicular to the plane of the loop (given at `t = 0`, `B = 0`, `I = 0)`. The value of the maximum current induced in the loop is A. `0.1 mA`B. `10 mA`C. `100 mA`D. Date insufficient |
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Answer» Correct Answer - C Induced e.m.f. `e = L(dI)/(dt) = A (dB)/(dt)` `rArr int_(0)^(1) dI = int_(0)^(B) (A)/(L) dB rArr I = (A)/(L) B` `rArr I_(max) = (A)/(L) B_(max) = (10^(-2))/(10 xx 10^(-3)) xx 0.1 = 0.1 A = 100 mA` |
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