1.

A closed pipe has certain frequency. Now its length is halved. Considering the end correction, its frequency will now becomeA. DoubleB. More than doubleC. Less than doubleD. Four time

Answer» Correct Answer - C
`n_1 = (v)/(4(l+e))`
and `n_2 = (v)/(4(l/2+e))= (2v)/(4(l+2e))`
Thus `n_2` is less than double of `n_1`


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