InterviewSolution
Saved Bookmarks
| 1. |
A closed pipe has certain frequency. Now its length is halved. Considering the end correction, its frequency will now becomeA. DoubleB. More than doubleC. Less than doubleD. Four time |
|
Answer» Correct Answer - C `n_1 = (v)/(4(l+e))` and `n_2 = (v)/(4(l/2+e))= (2v)/(4(l+2e))` Thus `n_2` is less than double of `n_1` |
|