A coil having 500 turns and diameter 0.3 m carries a current 0.2A calc

1.	A coil having 500 turns and diameter 0.3 m carries a current 0.2A calculate the intensity of magnetic field at the centre of coil
Answer» Answer:magnetic FIELD on the axis of circular loop is given by, where N is number of turns , i is current through circular coil or loop , x is distance between point of observation to CENTER of circular coil, R is the radius of circular coil. here, N = 50, i = 1A , R = 0.05m and x = 0.2m and we know, mkg/s²A² so, B = (4π × 10^-7 × 50 × 1 × 0.05²)/(0.2² + 0.05²)^3/2 = 0.0000179 Weber/m² = 1.79 × 10^-5 Weber/m² hence, magnetic field is 1.79 × 10^-5 Weber/m²

A coil having 500 turns and diameter 0.3 m carries a current 0.2A calculate the intensity of magnetic field at the centre of coil

Answer»

Answer:magnetic FIELD on the axis of circular loop is given by,

where N is number of turns , i is current through circular coil or loop , x is distance between point of observation to CENTER of circular coil, R is the radius of circular coil.

here, N = 50, i = 1A , R = 0.05m and x = 0.2m

and we know, mkg/s²A²

so, B = (4π × 10^-7 × 50 × 1 × 0.05²)/(0.2² + 0.05²)^3/2

= 0.0000179 Weber/m²

= 1.79 × 10^-5 Weber/m²

hence, magnetic field is 1.79 × 10^-5 Weber/m²

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A coil having 500 turns and diameter 0.3 m carries a current 0.2A calculate the intensity of magnetic field at the centre of coil

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