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A company which manufactures computers increases its production by 10% every year. In 2009 the company produced 80,000 computers. How many computers would it produced in 2011? |
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Answer» Here the number of computers produced every year is 10% more than the number produced the year before. So starting from 80,000. We have to find the number of computers produced every year after that for two years. Number of computers produced in 2009 = 80,000 Number of computers produced in 2010 = 80000 + 80000 × \(\frac{10}{100}\) = 80000 + 8000 = 88000 Number of computers produced in 2011 = 88000 + 88000 × \(\frac{10}{100}\) = 88000 + 8800 = 96800 |
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