A compound on treatment with hydrazine followed by heating up to 473K with KOH in ethylene glycol gives propane. Identify the compound.(a) Methanal(b) Ethanal(c) Propanal(d) AcetoneThe question was posed to me in homework.The above asked question is from Aldehydes and Ketones Chemical Reactions topic in division Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12

A compound on treatment with hydrazine followed by heating up to 473K

1.	A compound on treatment with hydrazine followed by heating up to 473K with KOH in ethylene glycol gives propane. Identify the compound.(a) Methanal(b) Ethanal(c) Propanal(d) AcetoneThe question was posed to me in homework.The above asked question is from Aldehydes and Ketones Chemical Reactions topic in division Aldehydes, Ketones and Carboxylic Acids of Chemistry – Class 12
Answer» Right OPTION is (d) Acetone The BEST I can EXPLAIN: Aldehydes and ketones are reduced to respective hydrocarbons when treated with hydrazine followed by heating with KOH/NaOH in high boiling solvents. This is known as Wolff-Kishner reduction. The CO GROUP of acetone is reduced to CH2, and propane is OBTAINED.

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