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A compound with molecular mass 180μ is acylated with CH3COCl, to get a compound with molecular mass 390μ. The number of amino groups present per molecule of the former compound is (a) 6 (b) 2 (c) 5 (d) 4 |
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Answer» The correct option is (c) 5. Explanation: Acylation of an amine group is represented as follows: RNH2 + CH3COCl ---> RNHCOCH3 + HCl Mass of product = 390 g Mass of amine = 180 g Increase in mass = 390- 180 g = 210 g Mass of one molecule of CH3CO = 12 + 3 + 12 + 16 = 43 Since, one hydrogen atom of NH2 group is replaced mass added per molecule = 43 - 1 = 42 g So, number of aceryl groups introduced = 210/42 = 5 Thus, number of amino groups in the original compound = 5 |
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