In complex MCl3.5H2O, the secondary valency of metal is 6 and it has n

1.	In complex MCl3.5H2O, the secondary valency of metal is 6 and it has no molecule of water present out of coordination sphere. Calculate the volume of 0.1M AgNO3 solution needed to precipitate the free chloride ions in 200 mL of 0.01 M solution of the complex.(a) 80mL(b) 40mL(c) 20mL(d) 120mLPS- The answer is (b) 40mL
Answer» Correct option is (b) 40ml As we have given, The secondary valency of metal = 6 and There is no molecule of water present out of coordination sphere. Therefore-- Molecular formula of complex will be--- [M(H₂O)₅Cl]Cl₂ In solution 1 mole of [M(H₂O)₅]Cl₂ gives 2 mole of chloride ions. \(\therefore\) 2 mole [M(H₂O)₅Cl]Cl₂ gives = 4 mole chloride ions. Let say V volume of 0.1 M AgNO₃ needed to precipitate free chloride ions present in 200 ml of 0.01 M [M(H₂O)₅Cl]Cl₂. \(\therefore\) 0.1 x V = 2 x(200ml x 0.01) V = 4/0.1 V = 40 ml

In complex MCl3.5H2O, the secondary valency of metal is 6 and it has no molecule of water present out of coordination sphere. Calculate the volume of 0.1M AgNO3 solution needed to precipitate the free chloride ions in 200 mL of 0.01 M solution of the complex.(a) 80mL(b) 40mL(c) 20mL(d) 120mLPS- The answer is (b) 40mL

Answer»

Correct option is (b) 40ml

As we have given,

The secondary valency of metal = 6

and There is no molecule of water present out of coordination sphere.

Therefore--

Molecular formula of complex will be---

[M(H₂O)₅Cl]Cl₂

In solution 1 mole of [M(H₂O)₅]Cl₂ gives 2 mole

of chloride ions.

\(\therefore\) 2 mole [M(H₂O)₅Cl]Cl₂ gives = 4 mole chloride ions.

Let say V volume of 0.1 M AgNO₃ needed to precipitate free chloride ions present in 200 ml of 0.01 M

[M(H₂O)₅Cl]Cl₂.

\(\therefore\) 0.1 x V = 2 x(200ml x 0.01)

V = 4/0.1

V = 40 ml

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