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a concave mirror produces a real image of magnification 1/2 when an object is placed at a distance of 50 cm from it where should be the object be placed so that a virtual image of double the size is formed by the mirror |
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Answer» Answer: Initial OBJ. dist = -60(real OBJECT) ". magnification (m) = -1/2 (as both obj and image are real) We know , m= -f/(u-f) [f=focal LENGTH] f= -20cm Now , obj dist = u' magnification(m')=2 (as image is virtual of real object) f=-20 CM We know , m= -f/(u'-f) 2=20/(u'+20) u'=-10cm Hence , the obj should at a distance of 10 cm in front of the mirror. |
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