A constant force acts on an object of mass 5 kg for a duration of 2sec

1.	A constant force acts on an object of mass 5 kg for a duration of 2sec it increases the velocity front 3 m/s to 7 m/ s find the of the applied force. now if the force was applied for a duration of 5 sec what would be the final velocity of object.
Answer» Let the FORCE be F, MASS is M, time for which it is accelerated = 2s velocity is increased from 3m/s to 7m/s so, acceleration is , a = (7-3)/2 = 2m/s² The force applied is, F = ma = (5)(2) = 10 N Now, the force is applied for 5S, the velocity after 5s will be, v=u+at => v =3+(2)(5) =>v=13m/s , this is FINAL velocity.

A constant force acts on an object of mass 5 kg for a duration of 2sec it increases the velocity front 3 m/s to 7 m/ s find the of the applied force. now if the force was applied for a duration of 5 sec what would be the final velocity of object.

Answer»

Let the FORCE be F,

MASS is M,

time for which it is accelerated = 2s

velocity is increased from 3m/s to 7m/s

so, acceleration is , a = (7-3)/2 = 2m/s²

The force applied is, F = ma = (5)(2) = 10 N

Now, the force is applied for 5S, the velocity after 5s will be,

v=u+at

=> v =3+(2)(5)

=>v=13m/s , this is FINAL velocity.

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A constant force acts on an object of mass 5 kg for a duration of 2sec it increases the velocity front 3 m/s to 7 m/ s find the of the applied force. now if the force was applied for a duration of 5 sec what would be the final velocity of object.

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