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A constant retarding force of 50 N is applied to a body of mass 20 kg moving intially with a speed of `15ms^(-1)` How long does the body take to stop ? |
Answer» Here, ` F = - 50 N, m = 20 kg , u = 15 ms^(-1) , upsilon = 0 , t = ? ` From ` F = ma , a = (F)/(m) = (-50)/(20) = - 2.5 ms^(-2) ` From ` upsilon = u + at ` ` 0 = 15 - 2.5 t ` ` t = (15)/(2.5) = 6 s`. |
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