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A converging lens has a focal length of `30 cm.` Rays from a `2.0 cm` high filament that pass through the lens from a virtual image at a distance of `50 cm` from the lens. Where is the filament located? What is the height of the image? |
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Answer» Correct Answer - A::C `1/-50-1/u=1/(+30)` Solving, we get `u=-18.75 cm` `m=v/u=((-50))/((-18.75))=2.67` `I=m(O)=2.67xx2` `=5.33 cm` |
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