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If the speed of light in ice is `2.3xx10^8 m//s,` what is its index of refraction? What is the critical angle of incidence for light going from ice to air? |
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Answer» Correct Answer - A::C `mu=c/v=(3xx10^8)/(2.3xx10^8)=1.3` `theta_C=sin^-1(1/mu)=sin^-1(1/1.3)=sin^-1(0.77)` |
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