1.

If the speed of light in ice is `2.3xx10^8 m//s,` what is its index of refraction? What is the critical angle of incidence for light going from ice to air?

Answer» Correct Answer - A::C
`mu=c/v=(3xx10^8)/(2.3xx10^8)=1.3`
`theta_C=sin^-1(1/mu)=sin^-1(1/1.3)=sin^-1(0.77)`


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