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A ray of light passes through two slabs of same thickness. In the first slab `n_(1)` waves are formed and in the second slab `n_2`. Find refractive ` ` index of second medium with respect to first. |
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Answer» Correct Answer - A::B One wave means one wavelength . So, if t is the thickness of slab, `lambda` the wavelength and `n` the number of waves, then `nlambda=t rArr lambda =t/n ` or `lambda prop (1)/(n)` (as `t` is same) or `(lambda_(1))/(lambda_(2) )= (n_(2))/(n_(1)) ` Now refractive, index of second medium `w.r.t.` first medium is `._(1)mu_(2) = (lambda_(1))/(lambda_(2)) = (n_(2))/(n_(1))` |
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