1.

a convex lens produces an inverted image magnified three times of an object placed at a 15cm from it. calculate the focal length of the lens.​

Answer»

<U>Answer:

FOCAL length of lens is +11.25 cm.

Step-by-step explanation-

Given:

[ Since the image is inverted, magnification will be -3]

  • u ( object distance ) = -15cm

To find:

  • focal length = ?

____..

We know that

{\boxed {\huge {\tt m=  \frac{<klux>V</klux>}{u}}}}

Where,

  • m is magnification
  • v is image distance
  • u is object distance

\tt  {\implies - 3 =  \frac{v}{ - 15}}

\tt {\implies v = ( - 3 )\times ( - 15)}

\tt\blue {\implies v = 45cm}

Now, ACCORDING to lens formula-

{\boxed {\huge {\tt  \frac{1}{v}  -  \frac{1}{u}  =  \frac{1}{f}}}}

Substituting values-

\tt { \longrightarrow \frac{1}{45}  -  \frac{1}{ -15}  =  \frac{1}{f} }

\tt { \longrightarrow \frac{1 + 3}{45}  =  \frac{1}{f}}

\tt { \longrightarrow \frac{4}{45}  =  \frac{1}{f}}

\tt\red { \longrightarrow f =  \frac{45}{4}}

[ After reciprocating both sides]

\tt\red { \longrightarrow f =   11.25}

Hence, the focal length of the lens is 11.25 cm.



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