A copper sphere of 100 g mass is beated to raise its temperature to 100^@C g mass is heated to raise its temperature to 100^@C and is released in water of mass 195 g and teperature 20^@C in a copper calorimeter. If the mass of clorimeter is 50 g. what will be the maximum temperature of water? (Give : specific heat of copper = 0.1 cal // g^@C and specific heat of calrimeter =0.1 " cal / g "^@C

A copper sphere of 100 g mass is beated to raise its temperature to 10

1.	A copper sphere of 100 g mass is beated to raise its temperature to 100^@C g mass is heated to raise its temperature to 100^@C and is released in water of mass 195 g and teperature 20^@C in a copper calorimeter. If the mass of clorimeter is 50 g. what will be the maximum temperature of water? (Give : specific heat of copper = 0.1 cal // g^@C and specific heat of calrimeter =0.1 " cal / g "^@C
Answer» Solution :LET copper sphere, water and calorimeter attain final temperature `T^@C` We have, Heat lost by copper sphere `Q=m_("sphere")xx C_("sphere")xx Delta T` `100 xx 0.1 xx (100-T)` Heat gained by water in calorimeter. `Q_1=m_("water")xxC_("water")xx Delta T` `=195 xx 1 xx (T-20)` Heat gained by calorimeter `Q_2=m_("calorimeter")xxC_("calorimeter")xx Delta T`. `= 50 xx 0.1xx (T -20)` According to princilple of heat exchange. `Q=Q_1+Q_2` `therefore10xx(100-T)=195 xx (T-20)+5 xx (T-20)` `therefore1000-10T=200(T-20)` `therefore 210 T= 5000` `therefore T =23.8^@C`