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a cricket ball is thrown at a speed of 28m/s in direction 30degree above the horizontal. then calculate a)maximum height b)time of flight c)horizontal distance take g=9.8 m/s^2 |
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Answer» HMAX= 28×28/4×2×9.8 = 49/4.9 = 10 time of FLIGHT 2vsin30/g = 28÷9.8 range = 28×28×√3/2×9.8 = 40√3 |
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