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A cricket ball of mass 150 g has an intial velocity u = `(3 hati + 4 hatj)ms^(-1)` and a final velocity `v = -(3hati + 4 hatj) ms^(-1)` , after being hit. The change in momentum (final momentum - initial momentum ) is (in `Kg ms^(1)`)A. zeroB. `-(0.45 hati+0.6 hatj)`C. `-(0.9 hati+1.2 hat j)`D. `-5( hati+hatj) hati` |
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Answer» Correct Answer - C ( c) Given,`u=(3 hati+4 hatj)ms^(-1) " and " v=-(3hati+4hatj) ms^(-1)` Mass of the ball=150g=0.15 kg `Deltap`=change in momentum = Final momentum-Initial momentum =mv-mu `=m(v-u)=(0.15)[-(3 hati +4 hatj)-(3 hati+4 hatj)]` `=(0.15)[-6hati-8hatj)]=-]0.15xx6hati+0.15 xx 8hatj)]` `=-[0.9 hati+1.2 hatj]` Hence, `Deltap=-[0.9 hati+1.2 hatj]` |
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