

InterviewSolution
Saved Bookmarks
1. |
A cricket ball of mass `150g` has an initial velocity `(3 hati + 4hatj)ms^(-1)` and a final velocity `upsilon = -(3hati + 4hatj)ms^(-1)` after beigh hit The change in momentum (final momentum initial momentum) is (in kg `ms^(-1)`)A. zeroB. `-(0.45hati + 0.6hatj)`C. ` -(0.9hati + 1.2hatj)`D. ` -5(hati + hatj)` |
Answer» Correct Answer - c Here, `m = 150g = 0.15kg , vec(u) = (3hati + 4hatj)m//s, vec(upsilon) = - (3hati + 4hatj)m//s` Change in momentum `vec (p) = m vec(upsilon) - m vec(upsilon) = 0.15 [-(3hati + 4hatj) -(3hati + 4hatj)] = - 0.30 [3hati + 4hatj)]` `vec(p) = - (0.9hati + 1.2hatj) kgm//s` . |
|