A cricket ball of mass 150g is moving with a velocity of 12m/s and hit

1.	A cricket ball of mass 150g is moving with a velocity of 12m/s and hitted by a bat so that the ball is turned back with a velocity of 20m/s. if the duration of contact btw the ball and bat is 0.01s.then:1. the impulse is----------------------
Answer» <P>The impulse of the ball is 4.8 Ns. Given data: Initially, velocity of the ball = 12 m/s Final velocity = 20 m/s Mass, m = 150 g = 0.15 kg To find: Impulse = ? SOLUTION: $\text {Impulse} =F \Delta t$ We KNOW that, $F=\frac{\Delta p}{\Delta t}$ Where, p is momentum Therefore, $\therefore \text {Impulse}=\frac{\Delta p}{\Delta t} \times \Delta t$ $\Rightarrow \text {Impluse}=\Delta p$ $\Delta p=m v_{2}-m v_{1}=m\left(v_{1}-v_{2}\right)$ $\Delta p=0.15 \times(-20-12)$ Since, the "rebound velocity" is taken negative in MOTION as the direction is changed. Thus, Impulse = 4.8 Ns