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A cricket ball of mass 70 g moving with a velocity 0.5 m/s is stopped by a player in 0.5 s. What is the force applied by the player to stop the ball? |
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Answer» Mass of the ball=70 gInitial Velocity(u)=0.5 m/sFinal velocity(v)=0Change in momentum=m(v-u)=-70×0.5×10⁻³=0.035 kgm/sTime taken=0.5 s∴Force applied to stop the ball=change in momemtum/time taken=0.07 N |
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