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InterviewSolution
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A cricketer can throw a ball to a maximum horizontal distance of 100 m. How high above the ground can the cricketer throw the same ball ? |
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Answer» Let u be the velocity of projection of the ball. The ball will cover maximum horizontal distance when angle of projection with horizontal, `theta=45^(@)`. Then `R_("max")=(u^(2))/(g)=100m` If ball is projected vertically upwards `(theta=90^(@))` from ground then H attains maximum value. `H_("max")=(u^(2))/(2g)=(R_("max"))/(2)` `therefore` the height to which cricketer can through the ball is `=(R_("max"))/(2)=(100)/(2)=50m`. |
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