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A cricketer has a certain average for 12 innings. In the thirteenth inning, he scored 78 runs, thereby increasing his average by 5 runs. His new average is:1). 18 runs2). 52 runs3). 55 runs4). 60 runs |
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Answer» We know that, Average = (Sum of all quantities)/(Number of quantities) Let INITIAL average = x ∴ x = (TOTAL runs scored in 12 innings)/12 Total runs scored in 12 innings = 12X ? He scored 78runs in 13th inning, Total runs scored in 13 innings = 12x + 78 ∴ New average = (12x + 78)/13 Since average increases by 5, $(\therefore {\RM{\;x}} + 5 = \frac{{{\rm{\;}}12{\rm{x\;}} + 78}}{{13}})$ ⇒ 13(x + 5) = 12x + 78 ⇒ 13x + 65 = 12x + 78 ⇒ x = 13 ∴ New average = 13 + 5 = 18 |
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