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A cubical block of side a is moving with velocity V on a horizontal smooth plane as shown in Figure. It hits a ridge at point O. The angular speed of the block after it hits O is A. `(3v)/(4a)`B. `(3v)/(2a)`C. `sqrt(3/2)a`D. zero |
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Answer» Correct Answer - A Conserving angular momentum about `O` (just before and just after ) is `mva/2=[(ma^(2))/6 (ma^(2))/2]omegaimplies omega=(3v)/(4a)` |
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