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A cubical block rests on an inclined plance of `mu = (1)/sqrt(3)` . Determine the angle at which the block just slides down the incline . |
Answer» Here , ` mu = (1)/sqrt(3) , alpha = ? ` When the block just slides down the incline , `theta = alpha` = angle of repose , when `tan alpha = mu = (1)/(sqrt (3)) :. alpha = 30^(@) ` . |
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