1.

A cubical tank of side 3.0 m is evacuated of air. That is, the number of molecules of air inside the tank is insignificant compared to thenumber in the same volume outside. The atmospheric pressure is 105 Pa. What is the crushing force exerted by the atmosphere ornthe tank ?

Answer»

P = F / A where

P is the pressure exerted on a body, F the force and A the area where the force is exerted.

The area of the cube is:

3 × 3 × 6 = 54M²

F = Pressure × Area

From the question:

Pressure = 10⁵ N/M²

Force = 10⁵ × 54

5400000N



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