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A cubical vessel of height `1` m is full of water. What is the workdone in pumping water out of the vessel? |
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Answer» Correct Answer - [4900 j] Let l be the length of each side of cube `rho` be the density of water. Mass of water in cubical vesssel, `m=l^(3) rho`. Mean heigh of water from ground, `h=l//2`. Workdone in pumping out the water is `W=mgh=l^(3)rhoxxgxxl//2=(1)/(2)l^(4)g rho` `=(1)/(2)xx1^(4)xx(9.8)xx(10^(3))=4900 j` |
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