A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.A. `(ll)/(4pi)`B. `(l^(2)l)/(4pi)`C. `(ll^(2))/(4pi)`D. `(l^(2)l^(2))/(4pi)`

A current I flows in a conducting wire of lenth L. If we bent it in a

1.	A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.A. `(ll)/(4pi)`B. `(l^(2)l)/(4pi)`C. `(ll^(2))/(4pi)`D. `(l^(2)l^(2))/(4pi)`
Answer» Correct Answer - B Length of a conducting wire, `2pir=l, r=(l)/(2pi)`, Area of coil, `alpha=pir^(2)=(pi.l^(2))/(4pi^(2))=(l^(2))/(4pi)` `So, " " m=lA=(ll^(2))/(4pi)`

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A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.A. `(ll)/(4pi)`B. `(l^(2)l)/(4pi)`C. `(ll^(2))/(4pi)`D. `(l^(2)l^(2))/(4pi)`

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