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A magnetic wire of dipole moment `4pi Am^(2)` is bent in the form of semicircle. The new magnetic moment isA. `4 pi Am^(2)`B. `8pi Am^(2)`C. `4 Am^(2)`D. None of these |
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Answer» Correct Answer - C Here, `M_(i)=4pi` `mL=4pi` `m=(4pi)/(L)` The new distance between poles is `L_(1)=2r=2(L)/(2pi)=(L)/(pi)` `therefore" "M_(f)=mL_(1)=(mL)/(pi)=(4pi)/(pi)` `=4Am^(2)` |
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