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A current of 1.0 A was passed for 2 hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (`Cu-63.5`)A. `79%`B. `39.5%`C. `63.25%`D. `63.5%`

Answer» Correct Answer - A
m(theoretical)`=(63.5xx0.1xx7200)/(96500)=0.4738g`
`therefore%` efficiency `=(0.3745)/(0.4738)xx100=79%`


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