1.

A current of 1A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16s would be roughly?

Answer»

`10^20`
`10^18`
`10^16`
`10^23`

Solution :As PER relation `I=(N E)/t,n=(It)/e=(1 TIMES 16)/(1.6 times 10^-19)=10^20`


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