Saved Bookmarks
| 1. |
A current of `9.65` ampere is passed through the aqueous solution `NaCI` using suitable electrodes for `1000s`. The amount of `NaOH` formed during electrolysis isA. 2.0 gB. 4.0 gC. 6.0 gD. 8.0 g |
|
Answer» Correct Answer - B `2H_(2)O+2e^(-)toH_(2)+2OH^(-)` No. of faraday passed `=(9.65xx1000)/(96500)=0.1F` `n_(OH^(-))` formed `=0.1` mol `nNaOH=0.1` mol `-=4gm` |
|