1.

A current of `9.65` ampere is passed through the aqueous solution `NaCI` using suitable electrodes for `1000s`. The amount of `NaOH` formed during electrolysis isA. 2.0 gB. 4.0 gC. 6.0 gD. 8.0 g

Answer» Correct Answer - B
`2H_(2)O+2e^(-)toH_(2)+2OH^(-)`
No. of faraday passed `=(9.65xx1000)/(96500)=0.1F`
`n_(OH^(-))` formed `=0.1` mol
`nNaOH=0.1` mol `-=4gm`


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