A current of 9.65 amperes is passed through three different electrolytes, i.e., NaNO_(3), KCl and ZnSO_(4) for 30 min separately. Calculate the mass ratio of the metals deposited at the respective electrodes. Also find out the weights of various metals deposited at the respective electrodes.

A current of 9.65 amperes is passed through three different electrolyt

1.	A current of 9.65 amperes is passed through three different electrolytes, i.e., NaNO_(3), KCl and ZnSO_(4) for 30 min separately. Calculate the mass ratio of the metals deposited at the respective electrodes. Also find out the weights of various metals deposited at the respective electrodes.
Answer» Solution :Quantity of electricity passed through the electrolyte = current `XX` time of flow `= 9.65 xx 30 xx 60` coulombs `m_(Na) : m_(K) : m_(Zn) = E_(Na) : E_(K) : E_(Zn)` `{:(E_(Na) = 23/1 = 23,, (Na^(+) + E^(-) to Na)),(E_(K) = 39/1 = 39,, (K^(+) + e^(-) to K)),(E_(Zn) = 65/2 = 32.5,, (Zn^(+2) + e^(-) to Zn)):}` `m_(Na) : m_(K) : m_(Zn) = 23 : 39 : 32.5` Weight of sodium deposited `= (23 xx 9.65 xx 30 xx 60)/(96500) = 4.14 G` Weight of POTASSIUM deposited `= (39 xx 9.65 xx 30 xx 60)/(96500) = 7.02 g` Weight of zinc deposited `= (32.5 xx 9.65 xx 30 xx 60)/(96500) = 5.85 g`