A Cycled From P To Q At 10 Kmph And Returned At The Rate Of 9 Kmph. B

1.	A Cycled From P To Q At 10 Kmph And Returned At The Rate Of 9 Kmph. B Cycled Both Ways At 12 Kmph. In The Whole Journey B Took 10 Minutes Less Than A. Find The Distance Between P And Q?
Answer» <P>Lets assume distance between P and Q = d km. Time TAKEN by A in both side = d/10 + d/9 = 19d/90 HRS. Time taken by B in both side = 2d/12 = d/6 hrs. B tool 10 min. or 1/6 hrs. less than A. So, 19d/90 - d/6 = 1/6 =&GT; (19d-15d)/90 = 1/6 => 4d/90 = 1/6 => d = 15/4 km = 3.75 km. Lets assume distance between P and Q = d km. Time taken by A in both side = d/10 + d/9 = 19d/90 hrs. Time taken by B in both side = 2d/12 = d/6 hrs. B tool 10 min. or 1/6 hrs. less than A. So, 19d/90 - d/6 = 1/6 => (19d-15d)/90 = 1/6 => 4d/90 = 1/6 => d = 15/4 km = 3.75 km.

A Cycled From P To Q At 10 Kmph And Returned At The Rate Of 9 Kmph. B Cycled Both Ways At 12 Kmph. In The Whole Journey B Took 10 Minutes Less Than A. Find The Distance Between P And Q?

Answer»

<P>Lets assume distance between P and Q = d km.

Time TAKEN by A in both side = d/10 + d/9 = 19d/90 HRS.

Time taken by B in both side = 2d/12 = d/6 hrs.

B tool 10 min. or 1/6 hrs. less than A.

So, 19d/90 - d/6 = 1/6

=&GT; (19d-15d)/90 = 1/6

=> 4d/90 = 1/6

=> d = 15/4 km = 3.75 km.

Lets assume distance between P and Q = d km.

Time taken by A in both side = d/10 + d/9 = 19d/90 hrs.

Time taken by B in both side = 2d/12 = d/6 hrs.

B tool 10 min. or 1/6 hrs. less than A.

So, 19d/90 - d/6 = 1/6

=> (19d-15d)/90 = 1/6

=> 4d/90 = 1/6

=> d = 15/4 km = 3.75 km.

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