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A cyclist goes round a circular track of `440` metres length in `20` seconds Find the angle that his cycle makes with the verticle. |
Answer» Correct Answer - `35^(@) 12` . Let r be radius of the track `2pi r = 440 m` `r = (440)/(2pi) m, upsilon = (2pi r)/(t) = (440)/(20) = 22ms^(-1)` As `tan theta = (upsilon^(2))/(rg)` `:. Tan theta =(22xx22xx2pi)/(440 xx 9.8) = 0.7055` `theta = 35^(@) 12` . |
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