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A cylinderical vessel is filled with water up to height H. A hole is bored in the wall at a depth h from the free surface of water. For maximum range h is equal toA. `H//4`B. `H//2`C. `3H//4`D. `H`

Answer» Correct Answer - B
Horizontal velocity of water out of hole, `u=sqrt(2 g h)`
Height of hole from ground level =(H - h). The time taken buy water to cover veertical distance (H - h) will be
`(H - h)=(1)/(2)g r^(2)` or `t= sqrt(2(H - h)//g)`
`:.` Horizontal range,
`R=u t =sqrt(2 g h)xx sqrt(2(H - h)//g)`
`=2sqrt(h(H - h))`
Horizontal range will be maximum if `dR//dh =0`
i.e., `2xx(1)/(2) (hH - h^(2))^(-1//2)xx(H-2 h)=0`
or `H=2 h` or `h=H//2`


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