A cylindrical conductor of length 1 and uniform area of cross section

1.	A cylindrical conductor of length 1 and uniform area of cross section A has resistance R. Another conductor of same material and resistance R has length 21. what will be it's area of cross section
Answer» Answer: area of CROSS section will be 2A Hi Aashritha , this is Anu (actually it is not 1 it is L , so kindly REPLACE the 1s with Ls) and check the answer below The resistance of a WIRE is R=ρ A/L which can ALSO be represented as A=ρ R/L where, ρ - Resistivity L - LENGTH A - Area of a cross-section ◇ WKT, the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance. ◇ In this case, the length of the conductor is doubled (2L) and so the resistance will be 2R. For the resistance to remain the same as R, the area of cross-section is also doubled as 2A. therefore, the area of cross-section is 2A.

A cylindrical conductor of length 1 and uniform area of cross section A has resistance R. Another conductor of same material and resistance R has length 21. what will be it's area of cross section

Answer»

Answer: area of CROSS section will be 2A

Hi Aashritha , this is Anu (actually it is not 1 it is L , so kindly REPLACE the 1s with Ls) and check the answer below

The resistance of a WIRE is

R=ρ A/L

which can ALSO be represented as

A=ρ R/L

where,

ρ - Resistivity

L - LENGTH

A - Area of a cross-section

◇ WKT, the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance.

◇ In this case, the length of the conductor is doubled (2L) and so the resistance will be 2R. For the resistance to remain the same as R, the area of cross-section is also doubled as 2A.

therefore, the area of cross-section is 2A.

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