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A cylindrical vessel of radius 0.5 m is filledwith oil at the rate of 0.25m3/minute. The rate at which thesurface of the oil is rising, is(a) 1 m/min.(b) 2 m/min. (c) 5 m/min. (d) 1.25 m/min.A. 1 m / minuteB. 2 m / minuteC. 5 m / minuteD. 1.25 m / minute |
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Answer» Correct Answer - A Let r be the radius, h be the height and V be the volume of the oil at time t. Then, `V=pir^(2)h` `impliesV=(pi)/(4)h" "[because r=0.5 m =(1)/(2)"(given)"]` `implies (dV)/(dt)=(pi)/(4)(dh)/(dt)` `implies 0.25 pi=(pi)/(4)xx(dh)/(dt) " "[because(dV)/(dt)=0.25 pi m^(3) "(given)"]` `implies (dh)/(dt)=1m//"minute"` |
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