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A detector is released from rest over a source of sound of frequency `f_(o) = 10^(3) H_(Z)`. The frequency observer by the decector at time `t` is plotted in the graph. The speed of sound in air `(g = 10 m//s^(2))` A. `330 m//s`B. `350 m//s`C. `300 m//s`D. `310 m//s` |
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Answer» Correct Answer - C `f = f_(o) ((nu + nu_(o))/(nu))` `= 10^(3) (1 + (10 t)/(nu))` (as `nu_(o) = g t`) Hence, `f` versus `t` graph is straight line of slope `(10^(4))/(nu)`. `:. (10^(4))/(nu) =` slope `= (100)/(3)` `:. nu = 300 m//s` |
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