1.

A disc having radius `R` is rolling without slipping on a horizontal (`x-z`) plane. Centre of the disc has a velocity `v` and acceleration `a` as shown. Speed of point `P` having coordinates `(x,y)` isA. `(vsqrt(x^(2)+y^(2)))/(R`B. `(vsqrt(x^(2)+(y+R)^(2)))/R`C. `(vsqrt(v^(2)+(y-R)^(2)))/R`D. none of these

Answer» Correct Answer - B
`omega=v/R`, Distance of `P` from origin
`r=sqrt(x^(2)+y^(2))`
origin is instantaneous centre of rotatio. So,
`v_(P)=omegar=(vsqrt(x^(2)+y^(2)))/R`


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