1.

A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?​

Answer»

\bf{\underline{Given}}:-

<P>
  • Lens of power (p) = 1.5 D

\bf{\underline{To\:Find}}:-

  • The FOCAL length of the lens.

\bf{\underline{Solution}}:-

we know that,

\blue{\bigstar}\:\:{\underline{\boxed{\bf\red{Power\:(p)=\dfrac{1}{f\:(in\:metres)}}}}}

\rm\longrightarrow\:1.5=\dfrac{1}{f}

\rm\longrightarrow\:f=\dfrac{1}{1.5}\:m

\rm\longrightarrow\:f=\dfrac{1}{1.5}\times\:10\:m

\rm\longrightarrow\:f=\cancel\dfrac{10}{15}\:m

\rm\longrightarrow\:f=\dfrac{2}{3}\:m

\rm\longrightarrow\:f=0.67\:m

Hence,the focal length of the lens will be 0.67 m.

The power of this lens is positive with a plus sign therefore,this is a convex lens or converging lens.

\blue{\bigstar}\:\:{\underline{\boxed{\bf\pink{More\: Information}}}}

Power of lens :- The power of a lens is DEFINED as the reciprocal of its focal length in metres.

  • A lens of short focal length has more power WHEREAS a lens of long focal length has less power.

  • The unit of power of lens is dioptres.

  • A power of convex lens is positive.


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