1.

A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

Answer»

75/2 days



Whole work is DONE by A in ( 20 x 5/4 ) = 25 days.

Now, ( 1 - 4/5 ) i.e., 1/5 work is done by A and B in 3 days.

Whole work will be done by A and B in (3 x 5) = 15 days
.
A's 1 day's work = 1/25 , (A + B)'s 1 day's work = 1/15
.
Therefore B's 1 day's work = ( 1/15 - 1/25 ) = 4/150 = 2/75
.
So, B ALONE would do the work in 75/2 days.



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