1.

A drop of olive oil of radius 0.30 mm spreads into arectangular film of 30 cm x 15 cm on the watersurface. Estimate the molecular size of olive oil.

Answer»

Here olive oil spread as a film, supposing it is 1 molecule thick on water surface, then the thickness of the film will give the estimate of diameter of molecule

So, we have

d = Volume of oil drop ÷ Area of film

d = 4/3 π (0.03)³ ÷ π (12)²

d = 4/3 (0.000027) ÷ 144

d = 0.000036 ÷ 144

d = 0.00000025

or d = 2.5 x 10^(-7) cm



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