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A drop of solution (volume `0.05 mL`) contains `3 xx 10^(-6) "mole" H^(o+)` ions. If the rate constant of disappearance of `H^(o+)` ions is `1 xx 10^(7) mol L^(-1) s^(-1)`, how long would it take for `H^(o+)` ions in the drop of disappear?A. `6 xx 10^(-8) sec`B. `6 xx 10^(-7) sec`C. `6 xx 10^(-9) sec`D. `6 xx 10^(-10) sec` |
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Answer» Correct Answer - C time Total for drop to disappears `(a_(0) - a_(t)) = k_(t) a_(t) = 0` `(3.0 xx 10^(-6))/((0.05 xx 10^(-3)) xx 1.0 xx 10^(-7)) = t_(100%)` `rArr t_(100%) = 6 xx 10^(-9) sec` Alternative method Units rate constant `= mol L^(-1) sec^(-1) rArr` Zero order reaction. `[A_(0)] - [A] = kT` `[A_(0)] = (3 xx 10^(-6) xx 100)/(0.05 xx 10^(-3)) = (3)/(50)` `(3)/(50) - 0 = kT` `rArr t = (3)/(50) xx (10^(-7))/(1)` `= 6 xx 10^(-9) sec` |
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